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Davidov

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How many 5-card poker hands consisting of three 8's and two cards that are not 8's are possible in a 52c deck?

can you help me solve? please and thank you =]]

Posted 792 day ago

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Answers (2)

fullhouse 		There are four 8s and you need 3, so that part is 4C3
There are 48 "not 8s" and you need two, so that part is 48C2
making the answer be 4C3 times 48C2
4•3•2 over 3•2•1 times 48•47 over 2•1

Posted 792 day ago

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Davido 		There are 4 8's in a deck of cards.For the first 8, there are 4 choices; for the second 8, 3 choices; for the third 8, 2 choices. So, there are 4*3*2/1*2*3 or 4 combinations of 3 8's. For the other two cards, the first can be chosen in 52-4(the 4 8's) or 48 ways and the second in 47 ways - a total of 48*47/1*2 or 1,128 combinations. So, the number of possible 5-card poker hands with three 8's and two non-8's is 4*1128 or 4,512.

Posted 792 day ago

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Question Title How many 5-card poker hands consisting of three 8's and two cards that are not 8's are possible in a 52c deck?
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